정현파 교류전압 \(e_1(t)\), \(e_2(t)\)가 다음과 같을 때, 두 전압의 합 \(e_1(t)+e_2(t)\)은 몇 V인가?
\(e_1(t)=10\sqrt{2}\,\sin\!\left(\omega t+\dfrac{\pi}{3}\right)\,[\mathrm{V}]\)
\(e_2(t)=20\sqrt{2}\,\cos\!\left(\omega t-\dfrac{\pi}{6}\right)\,[\mathrm{V}]\)
\(e_1(t)=10\sqrt{2}\,\sin\!\left(\omega t+\dfrac{\pi}{3}\right)\,[\mathrm{V}]\)
\(e_2(t)=20\sqrt{2}\,\cos\!\left(\omega t-\dfrac{\pi}{6}\right)\,[\mathrm{V}]\)
- 1\(30\sqrt{2}\,\sin\!\left(\omega t+\dfrac{\pi}{3}\right)\)
- 2\(30\sqrt{2}\,\sin\!\left(\omega t-\dfrac{\pi}{3}\right)\)
- 3\(10\sqrt{2}\,\sin\!\left(\omega t+\dfrac{2\pi}{3}\right)\)
- 4\(10\sqrt{2}\,\sin\!\left(\omega t-\dfrac{2\pi}{3}\right)\)
꿈라CBT